题目描述

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

 

输入描述:

Each input file contains one test case.  Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000.  The numbers are separated by a space.

输出描述:

For each test case, you should output the sum of a and b in one line.  The sum must be written in the standard format.

 

输入例子:

-1000000 9

 

输出例子:

-999,991

#include
     
      #include
      
       int str(int a){    int n=0;    while(a){        n++;        a/=10;    }    return n;}int main(){    int a,b,c,m,mm;    scanf("%d%d",&a,&b);    m=a+b;     if(m<0) mm = -m;    else mm = m;    c = str(a+b);    if(c<=3) printf("%d",m);    if(c>3&&c<=6){    printf("%d,%03d",m/1000,mm%1000);    }    if(c>6){        printf("%d,%03d,%03d",m/1000000,mm/1000%1000,mm%1000);    }}
      
     

 

 

这个题没什么特点，反复调整了几次，做完之后感觉并没有利用什么优秀的想法，于是看了一下别人的，好像大家都差不多，意外发现，实行了一下，好像DEV里不能用，日后有空再看一下。